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Glencoe Math: Course 3, Volume 2

GM

Glencoe Math: Course 3, Volume 2 View details

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Exercise 1 Page 368

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

b=86

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality.

49+b+45=180

Add terms

b+94=180

LHS-94=RHS-94

b=86

The solution to the equation is b=86.

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Quick Check p.368