We have 5 choices for the hundreds digit of our number. For the tens digit we have one less choice. For the ones digit we have one less choice than for the tens digits.
60
Practice makes perfect
We want to find the number of numbers that can be created from the given digits assuming that no digit should repeat.
9, 3, 4, 7, and 6
We have 5 choices for the hundreds digit of our number. For the tens digit we have 5-1 = 4 choices, and so on. By the Fundamental Counting Principle, the number of possible numbers is the product of choices we have for each of the digits.
5 * 4 * 3
Now, let's calculate this product.
5 * 4 * 3 = 60
