Since the pitcher should be the last one to bat, we arrange the order of the first batters from 9-1=8 players.
C
Practice makes perfect
There are 9 players that should bat and the pitcher is supposed to be the last one. Therefore, we arrange the other batters from 8 players. We have 8 choices for the first batter, 8-1= 7 choices for the second batter, and so on.
First Batter
Second Batter
Last Batter
8
8-1= 7
8-7=1
Now, we will use the Fundamental Counting Principle to find the answer. In this case, the number of ways to arrange these players is the product of these numbers of choices.
8 * (8-1) * (8-2)* (8-3) *(8-4)*(8-5)*(8-6)* (8-7)
=
8 * 7 * 6* 5* 4*3*2* 1
Now, let's calculate this product.
8 * 7 * 6* 5* 4*3*2*1 = 40 320
Therefore, answer C is correct.
