Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
7. Surface Area of Pyramids
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Exercise 1 Page 680

119.04 square centimeters

Practice makes perfect

The given solid is a pyramid.

To calculate the surface area of a pyramid, we can use the known formula where P is the perimeter of the base, l is the slant height, and B is the area of the base. S=1/2Pl+B The base of the pyramid is a square with the side length of 6.4 centimeters. Let's calculate its perimeter! P=4s ⇒ P&=4( 6.4) &= 25.6cm The area of the square equals the squared length of the side. B=s^2 ⇒ B&= 6.4^2 &= 40.96cm^2 We are also given that the slant height l is 6.1 centimeters. Let's substitute all of these values into the formula for the surface area and calculate it.

S=1/2Pl+B
S=1/2( 25.6)( 6.1)+ 40.96
â–¼
Simplify right-hand side
S=1/2(156.16)+40.96
S=156.16/2+40.96
S=78.08+40.96
S=119.04

The surface area of the pyramid is 119.04 square centimeters.