Exercise 27 Page 638

We are given a parallelogram with an area of 15.04 square meters and a height of 3.2 meters.

We want to find the base of the parallelogram. To do so, let's recall that the area of a parallelogram is the product of any base b and its height h. A= b h In this case, A= 15.04, and h= 3.2. Let's substitute these values into the formula. 15.04= b (3.2) Now we can solve the equation we got for b to find the base of the parallelogram. We can do this by using the Division Property of Equality.

15.04=b(3.2)

DivEqn

.LHS /3.2.=.RHS /3.2.

15.04/3.2=b(3.2)/3.2

CancelCommonFac

Cancel out common factors

15.04/3.2=b(3.2)/3.2

SimpQuot

Simplify quotient

15.04/3.2=b

CalcQuot

Calculate quotient

4.7=b

RearrangeEqn

Rearrange equation

b=4.7

We found that b= 4.7 is a solution to the equation. This means that the base of the parallelogram is 4.7 meters.