Glencoe Math: Course 2, Volume 2
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Glencoe Math: Course 2, Volume 2 View details
2. Area of Circles
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Exercise 12 Page 627

The area of a semicircle equals half the product of π and the square of its radius.

About 207.6ft^2

Practice makes perfect

We are told that a tunnel opening has the shape of the following semicircle.

Circle
We want to find the area of the tunnel opening. Recall that the area A of a semicircle equals half the product of π and the square of its radius r. A = 1/2 π r^2 Since the diameter of the tunnel opening is 23 feet, the radius of the tunnel opening is ( 12* 23) feet or 11.5 feet. Let's calculate the area using this information. We can use 3.14 as an estimation of π.
A = 1/2 π r^2
A = 1/2 π ( 11.5^2)

π ≈ 3.14

A ≈ 1/2 (3.14) (11.5^2)
A ≈ 1/2 (3.14) (132.25)
A ≈ 0.5 (3.14) (132.25)
A ≈ 207.6325
A ≈ 207.6
We found that A ≈ 207.6, which means that the area of the tunnel opening is about 207.6 square feet.