Exercise 20 Page 475

Start by using the Subtraction Property of Equality.

b = 24

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Multiplication Property of Equality.

25 + 11/12b = 47

SubEqn

LHS-25=RHS-25

25 + 11/12b - 25 = 47 - 25

SubTerms

Subtract terms

11/12b = 22

To isolate b, we can multiply both sides of the equation by the reciprocal of 1112.

11/12b = 22

MultEqn

LHS * 12/11=RHS* 12/11

11/12b* 12/11 = 22* 12/11

CommutativePropMult

Commutative Property of Multiplication

11/12* 12/11* b = 22* 12/11

MultFracByInverse

a/b* b/a=1

b = 22* 12/11

MoveLeftFacToNum

a*b/c= a* b/c

b = 22* 12/11

Multiply

b = 264/11

CalcQuot

Calculate quotient

b = 24

The solution to the equation is b = 24. We can check our solution by substituting it into the original equation.

25 + 11/12b = 47

Substitute

b= 24

25 + 11/12( 24) ? = 47

MoveRightFacToNum

a/c* b = a* b/c

25 + 11* 24/12 ? = 47

Multiply

25 + 264/12 ? = 47

CalcQuot

Calculate quotient

25 + 22 ? = 47

AddTerms

Add terms

47 = 47 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Hints

Check the answer

Practice exercises

Asses your skill