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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

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Exercise 19 Page 475

Start by using the Subtraction Property of Equality.

y = 4

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Division Property of Equality.

- 7y + 3 = - 25

LHS-3=RHS-3

- 7y + 3 - 3 = - 25 - 3

Subtract terms

- 7y = - 28

.LHS /- 7.=.RHS /- 7.

- 7y/- 7 = - 28/- 7

- a/- b=a/b

7y/7 = 28/7

Calculate quotient

y = 4

The solution to the equation is y = 4. We can check our solution by substituting it into the original equation.

- 7y + 3 = - 25

y= 4

- 7( 4) + 3 ? = - 25

Multiply

- 28 + 3 ? = - 25

Add terms

- 25 = - 25 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476