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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

Finish the assignment

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Exercise 9 Page 473

Start by using the Subtraction Property of Equality.

t=2.25

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Division Property of Equality.

4t + 3.5 = 12.5

LHS-3.5=RHS-3.5

4t + 3.5 - 3.5 = 12.5 - 3.5

Subtract terms

4t = 9

.LHS /4.=.RHS /4.

4t/4 = 9/4

Calculate quotient

t = 2.25

The solution to the equation is t=2.25. We can check our solution by substituting it into the original equation.

4t + 3.5 = 12.5

t= 2.25

4( 2.25) + 3.5 ? = 12.5

Multiply

9 + 3.5 ? = 12.5

Add terms

12.5 = 12.5 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476