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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

Finish the assignment

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Exercise 8 Page 473

Start by using the Addition Property of Equality.

r = 2.4

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Addition Property of Equality and Division Property of Equality.

2r - 3.1 = 1.7

LHS+3.1=RHS+3.1

2r - 3.1 + 3.1 = 1.7 + 3.1

Add terms

2r = 4.8

.LHS /2.=.RHS /2.

2r/2 = 4.8/2

Calculate quotient

r = 2.4

The solution to the equation is r = 2.4. We can check our solution by substituting it into the original equation.

2r - 3.1 = 1.7

r= 2.4

2( 2.4) - 3.1 ? = 1.7

Multiply

4.8 - 3.1 ? = 1.7

Subtract term

1.7 = 1.7 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476