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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

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Exercise 6 Page 473

Start by using the Subtraction Property of Equality.

b = - 49

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Multiplication Property of Equality.

5 + 1/7b = - 2

LHS-5=RHS-5

5 + 1/7b - 5 = - 2 - 5

Subtract terms

1/7b = - 7

LHS * 7=RHS* 7

1/7b* 7 = - 7 * 7

MoveRightFacToNumOne

1/b* a = a/b

b/7* 7 = - 7 * 7

FracMultDenomToNumber

a/7* 7 = a

b = - 7 * 7

Multiply

b = - 49

The solution to the equation is b = - 49. We can check our solution by substituting it into the original equation.

5 + 1/7b = - 2

b= - 49

5 + 1/7( - 49)? = - 2

a(- b)=- a * b

5 - 1/7(49) ? = - 2

MoveRightFacToNumOne

1/b* a = a/b

5 - 49/7 ? = - 2

Multiply

5 - 7 ? = - 2

Subtract term

- 2 = - 2 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476