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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

Finish the assignment

Continue to next subchapter

Exercise 3 Page 473

Start by using the Addition Property of Equality.

h = 7

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Addition Property of Equality and Division Property of Equality.

4h - 6 = 22

LHS+6=RHS+6

4h - 6 + 6 = 22 + 6

Add terms

4h = 28

.LHS /4.=.RHS /4.

4h/4 = 28/4

Calculate quotient

h = 7

The solution to the equation is h = 7. We can check our solution by substituting it into the original equation.

4h - 6 = 22

h= 7

4( 7) - 6 ? = 22

Multiply

28 - 6 ? = 22

Subtract term

22 = 22 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476