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Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

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Exercise 1 Page 473

Start by using the Subtraction Property of Equality.

x=3

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Division Property of Equality.

3x + 1 = 10

LHS-1=RHS-1

3x + 1 - 1= 10 - 1

Subtract terms

3x = 9

.LHS /3.=.RHS /3.

3x/3 = 9/3

Calculate quotient

x = 3

The solution to the equation is x=3. We can check our solution by substituting it into the original equation.

3x + 1 = 10

x= 3

3( 3) + 1 ? = 10

Multiply

9 + 1 ? = 10

Add terms

10 = 10 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476