body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Glencoe Math: Course 2, Volume 2

GM

Glencoe Math: Course 2, Volume 2 View details

4. Solve Two-Step Equations

Continue to next subchapter

Exercise 3 Page 472

Start by using the Subtraction Property of Equality.

n = - 12

Practice makes perfect

To solve an equation, we should isolate the variable term. In this case, we will use the Subtraction Property of Equality and Multiplication Property of Equality.

- 7 = 1 + 2/3n

LHS-1=RHS-1

- 7 - 1 = 1 + 2/3n- 1

Subtract terms

- 8 = 2/3n

To isolate n, we can multiply both sides of the equation by the reciprocal of 23.

- 8 = 2/3n

LHS * 2/3=RHS* 2/3

- 8 * 3/2 = 2/3n * 3/2

CommutativePropMult

Commutative Property of Multiplication

- 8 * 3/2 = 2/3 * 3/2* n

MultFracByInverse

a/b* b/a=1

-8 * 3/2 = n

MoveLeftFacToNum

a*b/c= a* b/c

- 8 * 3/2 = n

Multiply

- 24/2 = n

Calculate quotient

- 12 = n

Rearrange equation

n = - 12

The solution to the equation is n = - 12. We can check our solution by substituting it into the original equation.

- 7 = 1 + 2/3n

n= - 12

- 7 ? = 1 + 2/3( - 12)

MoveRightFacToNum

a/c* b = a* b/c

- 7 ? = 1 + 2(- 12)/3

Multiply

- 7 ? = 1 + - 24/3

Calculate quotient

- 7 ? = 1 + (- 8)

a+(- b)=a-b

- 7 = - 7 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Guided Practice p.472

Independent Practice p.473-474

H.O.T. Problems p.474

Standardized Test Practice p.474-476

Extra Practice p.475

Common Core Review p.476