6. Solve Inequalities by Addition or Subtraction
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{- 2}
We want to verify if any values contained in the replacement set are solutions of this equation. We will replace the variable with each value from the set and check if the equation is true for any of them.
| x | 6x=- 12 | Simplify | True or False? |
|---|---|---|---|
| - 3 | 6( - 3) ? =- 12 | - 18 ≠- 12 | False |
| - 2 | 6( - 2) ? =- 12 | - 12 = - 12 | True |
| - 1 | 6( - 1) ? =- 12 | - 6 ≠- 12 | False |
| 0 | 6( 0) ? =- 12 | 0 ≠- 12 | False |
| 1 | 6( 1) ? =- 12 | 6 ≠- 12 | False |
| 2 | 6( 2) ? =- 12 | 12 ≠- 12 | False |
| 3 | 6( 3) ? =- 12 | 18 ≠- 12 | False |
The equation is true when x=- 2. Therefore, the solution set is {- 2}.