Let's consider the given expression.
(a+b)(2+y)
We are asked to write an equivalent expression for the given expression using the Distributive Property. To do so, let's start by recalling this property. According to the Distributive Property, to multiply a sum or a difference by a number, we can multiply each term inside the parentheses by the number outside the parentheses.
1{{\color{#0000FF}{p}}( {\color{#009600}{q}}+{\color{#FD9000}{r}}) = {\color{#0000FF}{p}}{\color{#009600}{q}} + {\color{#0000FF}{p}}{\color{#FD9000}{r}} \\[0.3em] {\color{#0000FF}{p}}( {\color{#009600}{q}}-{\color{#FD9000}{r}}) = {\color{#0000FF}{p}}{\color{#009600}{q}} - {\color{#0000FF}{p}}{\color{#FD9000}{r}}}
Notice that the given expression is a product of two sums. We can think of (a+b) as the number and use the Distributive Property with this in mind.
(a+b)( 2+ y) = (a+b) (2)+ (a+b) (y)
Next, we can again use the Distributive Property to remove the parentheses.
