Glencoe Math: Course 2, Volume 1
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Glencoe Math: Course 2, Volume 1 View details
6. Sales Tax, Tips, and Markup
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Exercise 23 Page 158

To solve problems that involve percents, use the percent equation.

B

Practice makes perfect

We want to find how much change Ms. Taylor should have received for her purchase. Let's start by calculating the dollar amount of the sales tax using the percent equation. part = percent * whole We are given that Ms. Taylor bought a water tube that costs $ 87 plus 9 % sales tax. Let p represent the dollar amount of the sales tax. p = 9 % * $ 87We need to write the percent as a decimal before we can solve the equation that we created. We can do this by ignoring the percent symbol and moving the decimal point two places to the left.

percent as decimal: 0.0675

Therefore, 9 % is equal to 0.09. p = 9 % * $ 87 [0.3em] ⇓ [0.3em] p = 0.09 * $ 87 Now we can solve the equation for p. For simplicity, we will ignore the units for now.

p = 0.09 * 87
p = 7.83

We got that p= 7.83 is a solution to the equation. This means that Ms. Taylor paid $ 7.83 in sales tax. Now we can calculate the total cost of the tube. $87 + $ 7.83 = $ 94.83 The total cost of the tube with tax is $ 94.83. Ms. Taylor gave the cashier five $20 bills. Let's find how much change she should have received. 5* $ 20 - $ 94.83 = $ 100 - $ 94.83 = $ 5.17 We got that she should have received $ 5.17 in change, so the correct answer is B.