Glencoe Math: Course 2, Volume 1
GM
Glencoe Math: Course 2, Volume 1 View details
1. Rates
Continue to next subchapter

Exercise 25 Page 16

Find the unit rate — the average travel speed — for each day of the Jimenez family's road trip.

G

Practice makes perfect

We want to determine which day the Jimenez family averaged the greatest miles per hour. Let's start by summarizing all the information from the exercise in a table.

Day Distance Time
Sunday 300 miles 5 hours
Monday 200 miles 3 hours
Tuesday 150 miles 2.5 hours
Wednesday 250 miles 6 hours
We will find the average speed of the Jimenez family on each day. Let's start with Sunday. We know that on Sunday, the family traveled 300 miles in 5 hours. We can write a rate to show this situation. 300 m/5hRecall that a unit rate is a rate that has been reduced to a denominator of 1 unit. In this case, the unit rate is the number of miles per hour traveled by the family, which is their average speed. Let's find the unit rate! We can keep things simple by ignoring the units for now.
300/5
300/ 5/5/ 5
60/1
We found the unit rate! 300 mi/5h = 60 mi/1h As we can see, the family drove at an average speed of 60 miles per hour on Sunday. We can find the unit rate for Monday, Tuesday, and Wednesday by following the same steps.
Day Distance Time Rate Unit Rate
Sunday 300 miles 5 hours 300mi/5h 300mi ÷ 5/5h ÷ 5 = 60mi/1h
Monday 200 miles 3 hours 200mi/3h 200mi ÷ 3/3h ÷ 3 ≈ 66.7mi/1h
Tuesday 150 miles 2.5 hours 150mi/2.5h 150mi ÷ 2.5/2.5h ÷ 2.5 = 60mi/1h
Wednesday 250 miles 6 hours 250mi/6h 250mi ÷ 6/6h ÷ 6≈ 41.7mi/1h

Remember, the unit rate is the speed that the family traveled in miles per hour.

Day Unit Rate Average Speed
Sunday 60mi/1h 60 miles per hour
Monday ≈ 66.7mi/1h ≈ 66.7 miles per hour
Tuesday 60mi/1h 60 miles per hour
Wednesday ≈ 41.7mi/1h ≈ 66.7 miles per hour

We can see that the Jimenez family had the greatest average speed on Monday. This means that the correct answer is G.