Glencoe Math: Course 2, Volume 1
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Glencoe Math: Course 2, Volume 1 View details
1. Rates
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Exercise 6 Page 13

Find the average speed of each person from the given table and compare the results.

Susana, see solution.

Practice makes perfect

We are given the following table.

Name Event Time (s)
Tawni 50-m Freestyle 40.8
Pepita 100-m Butterfly 60.2
Susana 200-m Medley 112.4
We want to determine who swam the fastest. Let's find the average speed of each person from the table. We will find how many meters per second each person swam. Let's start with Tawni. We know that she swam 50 meters in 40.8 seconds. We can write a rate to show this situation. 50 m/40.8sRecall that a unit rate is a rate that has been reduced to a denominator of 1 unit. In this case, the unit rate is the number of meters per 1 second. Let's find the unit rate! For simplicity, we can temporarily ignore the units.
50/40.8
50/ 40.8/40.8/ 40.8
1.225490.../1
1.23/1
Finally, we got the unit rate. 50 m/40.8s ≈ 1.23 m/1s As we can see, Tawni's average speed is about 1.23 meters per second. We can find Pepita's and Susana's speeds by following the same steps.
Name Event Time (s) Rate Unit Rate
Tawni 50-m Freestyle 40.8 50m/40.8s 50m ÷ 40.8/40.8s ÷ 40.8 ≈ 1.23m/1s
Pepita 100-m Butterfly 60.2 100m/60.2s 100m ÷ 60.2/60.2s ÷ 60.2 ≈ 1.66m/1s
Susana 200-m Medley 112.4 200m/112.4s 200m ÷ 112.4/112.4s ÷ 112.4 ≈ 1.78m/1s

As we know, the unit rate is the number of meters per second swum by each person from the table.

Name Unit Rate Average Speed
Tawni ≈ 1.23m/1sec ≈ 1.23 meters per second
Pepita ≈ 1.66m/1sec ≈ 1.66 meters per second
Susana ≈ 1.78m/1sec ≈ 1.78 meters per second

We can see that Susana has the greatest average speed. This means that she swam the fastest!