Glencoe Math: Course 2, Volume 1
GM
Glencoe Math: Course 2, Volume 1 View details
Chapter Review

Exercise 5 Page 93

Begin by writing a rate that corresponds to the situation and use variable to represent the missing weight. Solve for the variable by using the Cross Products Property.

721.8 pounds

Practice makes perfect
Let's write the rate that corresponds to our situation. We can let the unknown weight be represented by the variable x. x pounds/9televisons = 240.6pounds/3televisions To solve the proportion, we will start by using the Cross Products Property.
x/9=240.6/3
3x=240.6(9)
3x=2165.4
3x/3=2165.40/3
x=721.8
We found that 9 televisions weigh 721.8 pounds.