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Evaluating and Interpreting Function Notation
Choose Course
Algebra 1
Functions
Evaluating and Interpreting Function Notation
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Evaluating and Interpreting Function Notation 1.6 - Solution
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Return to Evaluating and Interpreting Function Notation
a
Using the function
f
(
x
)
,
we want to evaluate for the given value,
f
(
0
)
.
To do this, we need to substitute
0
for
x
.
f
(
x
)
=
-
2
x
+
3
Substitute
x
=
0
f
(
0
)
=
-
2
⋅
0
+
3
Multiply
Multiply
f
(
0
)
=
0
+
3
AddTerms
Add terms
f
(
0
)
=
3
We have evaluated the function for
x
=
0
and found that
f
(
0
)
=
3
.
b
Here we want to calculate
f
(
4
)
.
Let's substitute
4
for
x
in the function rule
f
(
x
)
=
-
2
x
+
3
.
f
(
x
)
=
-
2
x
+
3
Substitute
x
=
4
f
(
4
)
=
-
2
⋅
4
+
3
Multiply
Multiply
f
(
4
)
=
-
8
+
3
AddTerms
Add terms
f
(
4
)
=
-
5
We are finished and we have found that
f
(
4
)
=
-
5
.
c
Here we are going to use the function rule
g
(
x
)
=
3
x
−
5
to find the value of
g
(
1
)
.
g
(
x
)
=
3
x
−
5
Substitute
x
=
1
g
(
1
)
=
3
⋅
1
−
5
Multiply
Multiply
g
(
1
)
=
3
−
5
SubTerm
Subtract term
g
(
1
)
=
-
2
Thus,
g
(
1
)
=
-
2
.
d
We want to find
g
(
-
3
)
.
We do that by substituting
-
3
for
x
in
g
(
x
)
=
3
x
−
5
.
g
(
x
)
=
3
x
−
5
Substitute
x
=
-
3
g
(
-
3
)
=
3
(
-
3
)
−
5
MultPosNeg
a
(
-
b
)
=
-
a
⋅
b
g
(
-
3
)
=
-
3
⋅
3
−
5
Multiply
Multiply
g
(
-
3
)
=
-
9
−
5
SubTerm
Subtract term
g
(
-
3
)
=
-
1
4
Above we have shown that
g
(
-
3
)
=
-
1
4
.
