Evaluating and Interpreting Function Notation

a

We can determine the value of $f (3)$ by substituting $3$ for $x$ and calculate the value of the expression.

f (x) = x^{2} - 2 x + 5

x = 3

f (3) = 3^{2} - 2 \cdot 3 + 5

CalcPowProdCalculate power and product

f (3) = 9 - 6 + 5

AddSubTermsAdd and subtract terms

f (3) = 8

b

In the same way, we substitute $x = 0$ into $f (x) .$

f (x) = x^{2} - 2 x + 5

x = 0

f (0) = 0^{2} - 2 \cdot 0 + 5

CalcPowProdCalculate power and product

f (0) = 0 - 0 + 5

AddSubTermsAdd and subtract terms

f (0) = 5

c

Nothing new — let's continue in the same way.

f (x) = x^{2} - 2 x + 5

x = - 3

f (- 3) = (- 3)^{2} - 2 \cdot (- 3) + 5

CalcPowProdCalculate power and product

f (- 3) = 9 + 6 + 5

AddTermsAdd terms

f (- 3) = 20

Evaluating and Interpreting Function Notation 1.2 - Solution