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Evaluating and Interpreting Function Notation
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Algebra 1
Functions
Evaluating and Interpreting Function Notation
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Evaluating and Interpreting Function Notation 1.12 - Solution
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Return to Evaluating and Interpreting Function Notation
a
To find the value of
x
that will make the function equal to
4
,
we will substitute
4
for
f
(
x
)
in the given function rule. Then we can solve for
x
.
f
(
x
)
=
3
1
x
+
2
Substitute
f
(
x
)
=
4
4
=
3
1
x
+
2
SubEqn
LHS
−
2
=
RHS
−
2
2
=
3
1
x
MultEqn
LHS
⋅
3
=
RHS
⋅
3
6
=
x
RearrangeEqn
Rearrange equation
x
=
6
When
x
=
6
,
the function equals
4
.
b
We have the function
g
(
x
)
=
2
3
x
+
2
.
Here we want to find the value of
x
for which
g
(
x
)
=
-
4
.
Let's do that by substituting
-
4
for
g
(
x
)
and solving the resulting equation for
x
.
g
(
x
)
=
2
3
x
+
2
Substitute
g
(
x
)
=
-
4
-
4
=
2
3
x
+
2
SubEqn
LHS
−
2
=
RHS
−
2
-
6
=
2
3
x
MultEqn
LHS
⋅
2
=
RHS
⋅
2
-
1
2
=
3
x
DivEqn
LHS
/
3
=
RHS
/
3
-
4
=
x
RearrangeEqn
Rearrange equation
x
=
-
4
We have found that
g
(
x
)
=
-
4
when
x
=
-
4
.