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Evaluating and Interpreting Function Notation

Evaluating and Interpreting Function Notation 1.1 - Solution

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a

We determine f(1)f(1) by substituting 11 for x,x, and evaluate.

f(x)=5x2f(x) = 5x - 2
f(1)=512f({\color{#0000FF}{1}}) = 5 \cdot {\color{#0000FF}{1}} - 2
f(1)=52f(1) = 5 - 2
f(1)=3f(1) = 3
b
We continue in the same way, by substituting 00 for x.x.
f(x)=5x2f(x) = 5x - 2
f(0)=502f({\color{#0000FF}{0}}) = 5 \cdot {\color{#0000FF}{0}} - 2
f(0)=02f(0) = 0 - 2
f(0)=-2f(0) = \text{-} 2
c
Here, we substitute -3\text{-}3 for x.x.
f(x)=5x2f(x) = 5x - 2
f(-3)=5(-3)2f({\color{#0000FF}{\text{-} 3}}) = 5 \cdot ({\color{#0000FF}{\text{-} 3}}) - 2
f(-3)=-152f(\text{-} 3) = \text{-} 15 - 2
f(-3)=-17f(\text{-} 3) = \text{-} 17