3. Solve Systems by Substitution
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(II):x= 8y-4
(II):Add terms
(II):LHS+4=RHS+4
(II): .LHS /16.=.RHS /16.
(II): a/b=.a /2./.b /2.
We will now substitute y= 58 into one of the equations to find the value of x. Let's use the first equation.
(I):y= 5/8
(I): 8 * a/8= a
(I): Subtract term
The solution to the given system of linear equations is the point (1, 58).
| What is done? | |
|---|---|
| Step I | Isolate one variable in any of the equations. |
| Step II | Substitute the equivalent expression of the isolated variable into the other equation. This will result in one equation in one variable. |
| Step III | Solve the obtained equation in one variable. |
| Step IV | Substitute the result into one of the original equations to find the other variable. |