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The sum of complementary angles is 90^(∘).
x=20^(∘) and y=43^(∘)
Consider the given diagram.
From the diagram, we can see that ∠2 and ∠3 are complementary and, therefore, the sum of their measures is 90^(∘).
m∠2 + m∠3 = 90^(∘)
The value of x is 20^(∘). From the diagram, we can see that the angle resulting from the sum of m∠2 and ∠3 is supplementary to ∠1. This means that the sum of their measures is 180^(∘). m∠1 +(m∠2+m∠3) = 180^(∘) We are told that m∠1 = (133-y)^(∘) and we know that m∠2+m∠3=90^(∘). Then, we can substitute these values into the above equation and solve the result for y. Again, we can ignore the symbol ^(∘) for the calculations.
m∠1= 133-y, m∠2+m∠3= 90
Add terms
LHS+y=RHS+y
Add terms
LHS-180=RHS-180
Subtract term
Rearrange equation
The value of y is 43^(∘).