Envision Math 2.0: Grade 7, Volume 2
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Envision Math 2.0: Grade 7, Volume 2 View details
Review

Exercise 3 Page 302

Practice makes perfect
To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. The variable term is already on the left hand side of the equation, so we will start by subtracting 3 from both hand sides of the equation.
4y+3=19
4y+3- 3=19- 3
4y=16
4y/4=16/4
y=4
The solution to the equation is y=4.

Checking Our Answer

We can check our solution by substituting it into the original equation.
4y+3=19
4( 4)+3? =19
16+3? =19
19=19 âś“
Since the left-hand side is equal to the right-hand side, our solution is correct.
Just as in the previous part, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. Here, we will start by adding 3 to both hand sides of the equation.
1/2n-3=5
1/2n-3+ 3=5+ 3
1/2n=8
1/2n * 2=8 * 2
n/2 * 2=8 * 2
n=8*2
n=16
The solution to the equation is n=16.

Checking Our Answer

Let's check our solution by substituting it into the original equation.
1/2n-3=5
1/2( 16)-3? =5
16/2-3? =5
8-3? =5
5=5 âś“
The left-hand side is equal to the right-hand side, so our solution is correct.