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Envision Math 2.0: Grade 7, Volume 2

EM

Envision Math 2.0: Grade 7, Volume 2 View details

Review

Exercise 2 Page 302

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality.

Steps:

Add 6 to both sides of the equation.
Divide both sides of the equation by 5.

Solution: x=10

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. The variable term is already on the left-hand side of the equation, so we will start by adding 6 to both sides of the equation.

5x-6=44

LHS+ 6=RHS+ 6

5x-6+ 6=44+ 6

Add terms

5x=50

Next, we will divide both sides of the equation by 5 to fully isolate x on the left-hand side.

5x=50

.LHS / 5.=.RHS / 5.

5x/5=50/5

Calculate quotient

x=10

The solution to the equation is x=10. Let's summarize the steps we performed to find the solution.

Add 6 to both sides of the equation.
Divide both sides of the equation by 5.

Checking Our Answer

We can check our solution by substituting it into the original equation. Let's do this!

5x-6=44

x= 10

5( 10)-6? =44

Multiply

50-6? =44

Subtract term

44=44 ✓

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Topic Essential Question p.301

Vocabulary Review p.301

Use Vocabulary in Writing p.301

1-2 Write Two-Step Equations | Solve Two-Step Equations p.302

3 Solve Equations Using the Distributive Property p.302

4 Solve Inequalities Using Addition or Subtraction p.303

5 Solve Inequalities Using Multiplication or Division p.303

6 Solve Two-Step Inequalities p.304

7 Solve Multi-Step Inequalities p.304