Exercise 16 Page 287

We want to complete the table. We can use the portion where both values are known to find the missing values.

Pages	9
Minutes	18	1	10	15

We know that we can read 9 pages in 18 minutes. Let's write this rate as a ratio. 9pages/18minutes or 9/18

We will use this ratio to find the missing values.

First Value

We can find an equivalent rate with a denominator of 1 to find how many pages we can read in 1 minute. We get this when we divide the numerator and the denominator by 18. Notice that we get the unit rate.

9/18

ReduceFrac

a/b=.a / 18./.b / 18.

9 ÷ 18/18 ÷ 18

CalcQuot

Calculate quotient

0.5/1

We can read 0.5 pages in 1 minute.

Pages	9	0.5
Minutes	18	1	10	15

Second Value

Now we want to find how many pages we can read in 10 minutes. We can use the unit rate 0.51 to find this missing value. To do this, we need to get an equivalent rate with a denominator of 10.

0.5/1

ExpandFrac

a/b=a * 10/b * 10

0.5* 10/1* 10

Multiply

Multiply

5/10

We can read 5 pages in 10 minutes.

Pages	9	0.5	5
Minutes	18	1	10	15

Third Value

To find the last value, we use the unit rate 251 again. This time we need an equivalent rate with a denominator of 15.

0.5/1

ExpandFrac

a/b=a * 15/b * 15

0.5* 15/1* 15

Multiply

Multiply

7.5/15

We can read 7.5 pages in 15 minutes.

Pages	9	0.5	5	7.5
Minutes	18	1	10	15