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{{ printedBook.courseTrack.name }} {{ printedBook.name }} Note that the given line is written in slope-intercept form. $y=2x−3⇔y=2x+(-3) $ Here $2$ is the slope and $-3$ is the $y-$intercept. We will use this information to graph the line.

To reflect this line in the $y-$axis, we will choose any two points on the line $y=2x−3$ and find their image after they have been reflected. Recall that reflection is performed through perpendicular segments.

We can now connect the obtained points to draw the image after the reflection.

To write the equation of the resulting line, we will note its slope.

We see above that the slope of the new line is $-2.$ We will use this and the fact that the line passes through $(-3,3)$ to write the equation in point-slope form. $y−3=-2(x−(-3))⇔y=-2x−3 $ Finally, we can label the line in our graph.