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log_2(m) + log_2(n)=log_2(mn)
Multiply
undoeach other. We can use this property to eliminate the logarithm in our equation!
2^(LHS)=2^(RHS)
2^(log_2(m))=m
Calculate power
LHS-8=RHS-8
Substitute values
| x=2+6/2 | x=8/2 | x=4 |
|---|---|---|
| x=2-6/2 | x=-4/2 | x=-2 |
We found that x can equal 4 or -2. Since we are dealing with logarithmic functions, we need to check the domain. Recall the equation before any transformations. log_2(x) + log_2(x-2) = 3 The argument of a logarithmic function must be positive. This means that arguments of both logarithms from our equation have to be positive. The solutions of these inequalities form the domain of our equation. Domain of the Equation: x > 0 and x-2 > 0 This means that x > 0 and x > 2, which simplifies into x > 2. Now let's check if the solutions are in the domain. 4 > 2 ✓ - 2 > 2 * Since x=-2 is not in our domain, we know that it is an extraneous solution. The solution of our equation is x = 4.
log(m) - log(n)=log(m/n)
10^(LHS)=10^(RHS)
10^(log_(10)(m))=m
a^(- m)=1/a^m
a/b=.a /x./.b /x.
Calculate power
LHS * 100=RHS* 100
a/100* 100 = a
a/c* b = a* b/c
Multiply
LHS * x=RHS* x
a/x* x = a
Rearrange equation