Core Connections Integrated III, 2015
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Core Connections Integrated III, 2015 View details
1. Section 9.1
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Exercise 57 Page 449

Write the equation by using the x-intercepts. Don't forget you have a double root at x=-2 and a single root at x=2. Calculate the stretch factor by substituting any point from the graph into the formula.

y=- 1/4(x+2)(x+2)(x-2)

Practice makes perfect

Examining the coordinate plane, we notice that the graph has a double root at x=-2 and a single root at x=2.

Factored Form

If a polynomial has the roots x=a and x=b we can write its factors as follows. &(x-a) &(x-b)By substituting a=-2 and b=2 into the expressions above, we can determine the linear factors. (x-(-2)) &⇔ (x+2) (x-(2)) &⇔ (x-2) Since the first root is a double root so we must include this factor twice. With this information, we can write the function in factored form. y=k(x+2)(x+2)(x-2)

Stretch Factor

To determine the stretch factor k, we have to substitute a point that falls on the graph of the function into the equation and solve for k. We can pick any point we like except for the x-intercepts. Let us pick the y-intercept (0,2).

y=k(x+2)(x+2)(x-2)
2=k( 0+2)( 0+2)( 0-2)
â–¼
Solve for k
2=k(2)(2)(-2)
2=-8k
-2=8k
8k=-2
k=-2/8
k=-1/4

The stretch factor is k=- 14.

Completing the Function

By substituting the stretch factor into the equation, we can complete the function. y=- 1/4(x+2)(x+2)(x-2)