Core Connections Integrated III, 2015
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Core Connections Integrated III, 2015 View details
1. Section 9.1
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Exercise 25 Page 440

Practice makes perfect
a Examining the diagram, we see that this is a right triangle where one of the non-right angle is 30^(∘). This fits the description of a 30-60-90 triangle. In such a triangle, the hypotenuse is always twice as long as the shorter leg, and the longer leg is sqrt(3) times as long as the shorter leg. Let's illustrate this.
In the given triangle, the hypotenuse is x. Therefore, we get the following equation. x=2a Since we know the value of a in the given triangle is 12, we can determine x.
x=2a
x=2( 1/2)
x=2/2
x=1
b Examining the diagram, we can see that the triangle has a 45^(∘)-angle and a right angle. This makes it a 45-45-90 triangle. In such a special triangle, the hypotenuse is always sqrt(2) times longer than its legs.
In the given triangle, the hypotenuse is 1. We get the following equation asqrt(2)=1 Let's solve for a, which is the same as x in the given triangle.
asqrt(2)=1
a=1/sqrt(2)
The triangle's leg is 1sqrt(2) units.