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Core Connections Integrated III, 2015 View details

1. Section 6.1

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Exercise 30 Page 279

Equate the function's right-hand sides and solve for x.

(- 6,1/2), and (6,1/2)

Practice makes perfect

By setting the function's right-hand sides equal and solving for x, we can find the coordinates where the graphs of the functions intersect.

1/2=16/x^2-4

MultEqn

LHS * (x^2-4)=RHS* (x^2-4)

x^2-4/2=16

MultEqn

LHS * 2=RHS* 2

x^2-4=32

AddEqn

LHS+4=RHS+4

x^2=36

SqrtEqn

sqrt(LHS)=sqrt(RHS)

x_(1,2)=± 6

The functions intersect at x=- 6 and x=6. Notice that we already know that the y-value is 12, since one of the functions is a horizontal line through this value. (- 6, 12), and (6, 12)