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The graphs of a function and its inverse are symmetric to each other with respect to the line y=x.
Equation: f^(-1)(x) = sqrt(2x)-1
Graph:
To graph the given function, we can make a table of values to find the points on the graph.
| x | 1/2(x+1)^3 | f(x)=1/2(x+1)^3 |
|---|---|---|
| -3 | 1/2( -3+1)^3 | -4 |
| -2 | 1/2( -2+1)^3 | -1/2 |
| -1 | 1/2( -1+1)^3 | 0 |
| 0 | 1/2( 0+1)^3 | 1/2 |
| 1 | 1/2( 1+1)^3 | 4 |
Let's plot and connect the obtained points.
| Points | Reflection across y=x |
|---|---|
| ( -3, -4) | ( -4, -3) |
| ( -2, -1/2) | ( -1/2, -2) |
| ( -1, 0) | ( 0, -1) |
| ( 0, 1/2) | ( 1/2, 0) |
| ( 1, 4) | ( 4, 1) |
Once again, let's add the points to the graph and connect them.
Now we should move on to finding the equation of the inverse. Before we do it we will rewrite the given function as an equation relating x and y. f(x)=1/2(x+1)^3 ⇒ y=1/2(x+1)^3 To algebraically determine the inverse of the given relation, we exchange x and y and solve for y. c|c Given Equation & Inverse Equation [0.8em] y=1/2( x+1)^3 & x=1/2( y+1)^3 The result of isolating y in the new equation will be the inverse of the given function.
LHS * 2=RHS* 2
sqrt(LHS)=sqrt(RHS)
( sqrt(a) )^n = a
LHS-1=RHS-1
Rearrange equation
Now that we have isolated y, we have found the equation of the inverse of the given function. y=sqrt(2x)-1 ⇒ f^(-1)(x) = sqrt(2x)-1