Exercise 200 Page 558

If we write this series as a list of numbers, it is an arithmetic sequence that has a first term of t(1)= 3 and a common difference of d= 3. 3, 6, 9, ..., 30 We can find an explicit formula for this sequence.

Now we can use the explicit formula to find the position n of the last term in the series, 30.

The upper limit is 10. Finally, let's write the summation notation of the series! ∑^()darkorange10_(n=1) 3n

If we write this series as a list of numbers, it is an arithmetic sequence that has a first term of t(1)= - 7 and a common difference of d= 3. - 7, -4, -1, 2, 5, 8, 11 Let's find the explicit formula for this sequence.

Notice that all terms of our series are listed. This means that we can count the number of terms instead of needing to find this information algebraically. In our exercise, the upper limit — the number of terms in the series — is 7. Finally, let's write the summation notation of the series! ∑^7_(n=1) 3n -10