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Is sequence arithmetic, geometric, or neither? Sequence is geometric.
Is sequence arithmetic, geometric, or neither? Neither.
Is sequence arithmetic, geometric, or neither? Both arithmetic and geometric.
We are given the following recursive rule for our sequence.
a_1&=17
a_(n+1)&= - a_n, for n ≥ 1
| n | a_(n+1) = - a_n | - a_(n-1) | a_n |
|---|---|---|---|
| - | - | - | 17 |
| 1 | a_(1+1)=- a_1 | - a_1=-( 17) | -17 |
| 2 | a_(2+1)=- a_2 | - a_2=-( -17) | 17 |
| 3 | a_(3+1)=- a_3 | - a_3=-(17) | -17 |
| 4 | a_(4+1)=- a_4 | -a_4=-(-17) | 17 |
Therefore, the first 5 terms of the sequence are 17, -17, 17, -17, and 17. Now, let's identify whether the sequence is arithmetic, geometric, or neither.
When a sequence is arithmetic, the difference between two consecutive terms is constant. Examining our sequence, we can see that this is not the case. 17 -34 → -17 +34 → 17 -34 → -17 +34 → 17 Therefore, the sequence is not arithmetic. Next, let's check whether the sequence is geometric.
When a sequence is geometric, the ratio between two consecutive terms is constant. Examining our sequence, we can see that this is the case. 17 *(-1) → -17 *(-1) → 17 *(-1) → -17 *(-1) → 17 Therefore, the sequence is geometric and the common ratio is -1.
We are given the following recursive rule for our sequence.
a_1&=32
a_(n+1)&= -5 + 12 a_n, for n ≥ 1
| n | a_(n+1) = -5 + 12 a_n | -5 + 12 a_n | a_n |
|---|---|---|---|
| - | - | - | 32 |
| 1 | a_(1+1)=-5 + 12 a_1 | -5 + 12 a_1=-5 + 12( 32) | 11 |
| 2 | a_(2+1)=-5 + 12 a_2 | -5 + 12 a_2=-5 + 12( 11) | 0.5 |
| 3 | a_(3+1)=-5 + 12 a_3 | -5 + 12 a_3=-5 + 12(0.5) | -4.75 |
| 4 | a_(4+1)=-5 + 12 a_4 | -5 + 12 a_4=-5 + 12(-4.75) | -7.375 |
Therefore, the first 5 terms of the sequence are 32, 11, 0.5, -4.75, and -7.375. Now, let's identify whether the sequence is arithmetic, geometric, or neither.
When a sequence is arithmetic, the difference between two consecutive terms is constant. Examining our sequence, we can see that this is not the case. 32 -21 → 11 -10.5 → 0.5 -5.25 → -4.75 -2.625 → -7.375 Therefore, the sequence is not arithmetic. Next, let's check whether the sequence is geometric.
When a sequence is geometric, the ratio between two consecutive terms is constant. Examining our sequence, we can see that again this is not the case. 32 ≈ *0.34 → 11 ≈ *0.05 → 0.5 * (-9.5) → -4.75 * 1.55 → -7.375 Therefore, the sequence is geometric arithmetic. Therefore, our sequence is neither arithmetic nor geometric.
We are given the following recursive rule for our sequence.
a_1&=81
a_(n+1)&= a_n, for n ≥ 1
| n | a_(n+1) = a_n | a_n | a_n |
|---|---|---|---|
| - | - | - | 81 |
| 1 | a_(1+1)=a_1 | a_1= 81 | 81 |
| 2 | a_(2+1)=a_2 | a_2= 81 | 81 |
| 3 | a_(3+1)=a_3 | a_3=81 | 81 |
| 4 | a_(4+1)=a_4 | a_4=81 | 81 |
Therefore, the first 5 terms of the sequence are 81, 81, 81, 81, and 81. Now, let's identify whether the sequence is arithmetic, geometric, or neither.
When a sequence is arithmetic, the difference between two consecutive terms is constant. Examining our sequence, we can see that this is not the case. 81 +0 → 81 +0 → 81 +0 → 81 +0 → 81 Therefore, the sequence is not arithmetic. However, we are not done yet, as the sequence might also be geometric!
When a sequence is geometric, the ratio between two consecutive terms is constant. Examining our sequence, we can see that again this is not the case. 81 *1 → 81 *1 → 81 *1 → 81 *1 → 81 Therefore, the sequence is geometric arithmetic. Therefore, our sequence is neither arithmetic nor geometric.