Core Connections: Course 2
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Core Connections: Course 2 View details
2. Section 5.2
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Exercise 32 Page 258

Practice makes perfect
We want to determine the area of the given figure. Let's look at the diagram!

Notice that the figure is a is a quadrilateral with two pairs of parallel sides. This means that our figure is a parallelogram. We can recall that the area of a parallelogram is the product of its base and its height. A=bh Now, we can identify the base and height of the parallelogram on the diagram.

In the given parallelogram, we can consider the side whose length is 27 inches at the base and its corresponding height is 17 inches. We can substitute these two values into the formula for the area of a parallelogram and simplify.

A=bh
A= 27(17)
A=459

The area of the parallelogram is 459 square inches.

We want to determine the area of the given figure. Let's look at the diagram!

Notice that the figure is a is a polygon with with three angles and three sides. This means that our figure is a triangle. We can recall the formula for the area of a triangle. A=1/2bh In this formula, b is the length of the base and h is the height. Now, we can identify the base and height of the triangle on the diagram.

For our triangle, we will substitute b= 20.75 for the base and h= 9 for the height into the formula to calculate A.

A=1/2bh
A=1/2( 20.75)( 9)
A=20.75/2* 9
A=10.375* 9
A=93.375
A≈ 93.38

The area of the triangle is 93.38 square meters.