body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Core Connections Algebra 2, 2013

CC

Core Connections Algebra 2, 2013 View details

3. Section 8.3

Continue to next subchapter

Exercise 173 Page 428

Substitute x=-2 into the given equation and then evaluate.

It is not. See solution.

Practice makes perfect

We can determine whether x=-2 is a solution by substituting it into the equation and simplifying using the order of operations.

x^4-4x = 8x^2-40

x= -2

( -2)^4-4( -2) ? = 8( -2)^2-40

▼

Evaluate

Calculate power

16 - 4(-2) ? = 8(4) - 40

MultNegNegOnePar

- a(- b)=a* b

16 + 8 ? = 8(4) - 40

Multiply

16 + 8 ? = 32 - 40

Add and subtract terms

24 ≠ -8 *

Since the sides are not equal, x = -2 is not a solution to the given equation.

Subchapter links

8.3.1 Polynomial Division p.411-413

8.3.2 Factors and Integral Roots p.419-424

8.3.3 An Application of Polynomials p.427-429