The equation has two roots. With this information, we can factor the expression by substituting a= sqrt(10) and b= - sqrt(10) in the expression (x- a)(x- b).
(x- sqrt(10))(x-( - sqrt(10)))
⇓
(x-sqrt(10))(x+sqrt(10))
b Again, we will start by setting the equation equal to zero.
The equation has two roots. With this information, we can factor the expression by substituting a= 3+sqrt(37)2 and b= 3-sqrt(37)2 into the form (x- a)(x- b).
(x- 3+sqrt(37)2)(x- 3-sqrt(37)2)
c Let's start by setting the polynomial equal to 0 and solving the equation.
The equation has two roots. With this information, we can factor the expression by substituting a= 2i and b= - 2i in the form (x- a)(x- b).
(x- 2i)(x-( - 2i))
⇓
(x-2i)(x+2i)
d Again, we will start by setting the equation equal to zero.
x^2-2x+2=0To solve this equation, we can use the Quadratic Formula.
The equation has two roots. With this information, we can factor the expression by substituting a= 1+i and b= 1-i in the form (x- a)(x- b).
(x-( 1+i))(x-( 1-i))
