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f(x)=2x-3 ⇔ y=2x-3
Now, to algebraically determine the inverse of the equation we exchange x and y and solve for y.
Finally, we write the inverse of the given function in function notation by replacing y with f^(- 1)(x) in our new equation. f^(- 1)(x)=x+3/2
y=( x-3)^2+2 ↓ x=( y-3)^2+2
LHS-2=RHS-2
sqrt(LHS)=sqrt(RHS)
sqrt(a^2)=± a
Rearrange equation
LHS+3=RHS+3
Finally, to indicate that this is the inverse function of h(x), we replace y with h^(- 1)(x). h^(- 1)(x)= ± sqrt(x-2) + 3 Note that h^(- 1)(x) is not a function. By taking the square root, we created a positive value and a negative value. This gives two outputs for each input, and so by definition it is not a function.