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any number?
(any number)* x^((whole number)) Let's rewrite some of the variables and the constant, and check if it follows the description of a polynomial. ( any number)* x^(( whole number)) ↓ f(x)= 3x^3- 2x^2+ 5x^0 As we can see, the equation is a polynomial. The highest power is 3, which means the polynomial is of the third degree.
( any number)* x^(whole number) ↓ y= 0.25x^7- 5x^1 The equation is a polynomial. The highest power is 7, which means the polynomial is of the seventh degree.
( any number)* x^(whole number) ↓ y= 3^x+ 1x^2 The equation is not a polynomial.
( any number)* x^(whole number) ↓ f(x)= 1x^2- 1x^(0.5)+ 2x^0 Since 0.5 is not a whole number, the expression is not a polynomial.
(a+b)^2=a^2+2ab+b^2
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( any number)* x^(whole number) ↓ y= 1x^2- 3x^1+ 5x^0- 2(x-2)^(- 1) The equation is not a polynomial.