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Points (1,18) and (4,3888) must satisfy the given equation.
Points (-2,-8) and (3,-0.25) must satisfy the given equation.
y=3*6^x
y=-2(0.5)^x
We want to write an exponential function for the graph that passes through the points (1,18) and (4,3888). Let's consider the general form for this type of function.
y=ab^x Since we want the points to lie on the graph, they must satisfy this equation. Let's substitute (1,18) into the above formula.
We received two equations, so to find the values of a and b we need to solve the system of equations. ab=18 & (I) ab^3=3888 & (II) The first equation says that the product of a and b is 18. Notice that the second equation contains the same expression multiplied by b^3. ab=18 ab^4=3888 ⇒ ab=18 ab* b^3=3888 This allows us to substitute the value of ab into the second equation and solve for b.
(II): ab= 18
(II): .LHS /18.=.RHS /18.
(II): sqrt(LHS)=sqrt(RHS)
(II): sqrt(a^3)=a
(II): Calculate root
Now that we know the value of b, let's substitute it into the first equation to find a.
Finally, we can write the full equation of the function. y= a b^x ⇒ y= 3* 6^x
Similarly, we can find the equation of the function passing through (-2,-8) and (3,-0.25). Let's substitute the first point into the general equation.
x= -2, y= -8
a^(- m)=1/a^m
a* 1/b= a/b
Rearrange equation
Next, we will substitute the second given point, (3,-0.25).
x= 3, y= -0.25
Rearrange equation
Write as a fraction
(II): a= -8 b^2
(II): a^m*a^n=a^(m+n)
(II): .LHS /(-8).=.RHS /(-8).
(II): .a/b /c.= a/b* c
(II): Put minus sign in front of fraction
(II): sqrt(LHS)=sqrt(RHS)
(II): sqrt(a^5)=a
(II): sqrt(a/b)=sqrt(a)/sqrt(b)
Once we know the value of b, let's substitute it to the first equation to find a.
(I): b= 1/2
(I): (a/b)^m=a^m/b^m
(I): a* 1/b= a/b
(I): Calculate quotient
Finally, we can write the full equation of the function. y= -2( 1/2)^x ⇔ y= -2( 0.5)^x