Core Connections Algebra 2, 2013
CC
Core Connections Algebra 2, 2013 View details
1. Section 7.1
Continue to next subchapter

Exercise 40 Page 326

The x-intercept is the point of intersection of the function with the x-axis. Similarly, the y-intercept is the point of intersection with the y-axis.

x-intercepts: -3±sqrt(6)/3
y-intercept: 1

Practice makes perfect

We want to find the x- and y-intercepts of a quadratic function. Let's begin with the x-intercept.

Finding the x-intercept

Think of the point where the graph of an equation crosses the x-axis. This is the x-intercept. The y-value of that ( x, y) coordinate pair is 0, so to find the x-intercept of the equation we should substitute 0 for y and solve for x.

y=3x^2+6x+1
0=3x^2+6x+1

We got a quadratic equation. To solve it we can use the Quadratic Formula.

ax^2+ bx+ c=0 ⇕ x=- b± sqrt(b^2-4 a c)/2 a Let's identify the values of a, b, and c in our case. 0=3x^2+6x+1 ⇓ 3x^2+ 6x+ 1=0 We can see that a= 3, b= 6, and c= 1. Let's substitute these values into the Quadratic Formula.

x=- b±sqrt(b^2-4ac)/2a
x=- 6±sqrt(6^2-4( 3)( 1))/2( 3)
â–¼
Solve for x and Simplify
x=-6±sqrt(36-4(3)(1))/2(3)
x=-6±sqrt(36-12)/6
x=-6±sqrt(24)/6
x=-6±sqrt(4*6)/6
x=-6±sqrt(4)*sqrt(6)/6
x=-6±2*sqrt(6)/6
x=2(-3±sqrt(6))/6
x=-3±sqrt(6)/3

The solutions for this equation are x= -3±sqrt(6)3. These are the x-intercepts.

Finding the y-intercept

Let's use the same concept to find the y-intercept. Consider the point where the graph of the equation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.

y=3x^2+6x+1
y=3( 0)^2+6( 0)+1
y=0+0+1
y=1

A y-intercept of 1 means that the graph passes through the y-axis at the point (0, 1).