Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 7.1
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Exercise 39 Page 326

Practice makes perfect
a

We are given approximations of log2, log3, and log5. This allows us to approximate other logarithms. To do so, we will first recall three useful Properties of Logarithms.

Properties of Logarithms
Name Product Property Quotient Property Power Property
Condition a>0, b>0, and x ≠ 1 a>0, b>0, and x ≠ 1 m>0, b>0, and b ≠ 1
Property log_x ab = log_x a + log_x b log_x ab=log_x a - log_x b log_b m^p = p log_b m

To find the approximation of log6, we should write it in terms of the given logarithms. According to the Product Property, the logarithm of a product is the same as the sum of the logarithms of its factors. Note that 6 is a product of 2 and 3. log6=log(2* 3) This means we can rewrite the logarithm as a sum. log(2* 3)=log2+log3 Now, we can substitute the given values and find log6.

log2+log3
0.3010+ 0.4771
0.7781

Therefore, log6≈0.7781.

b

Similarly as in Part A, we will use the Properties of Logarithms to write log15 in terms of the given logarithms. In this case, note that 15 is the product of 3 and 5.

log15 = log(3*5)By the Product Property of Logarithms, we can rewrite it as a sum of the logarithms of factors. log(3*5) = log3+log5 Let's substitute the given approximations and find log15.

log3+log5
0.4771+ 0.6990
1.1761

Therefore, log15≈ 1.1761.

c

Once again, to find the approximation of log9 we will use the Properties of Logarithms. According to the Power Property, the logarithm of a power is the product of the logarithm and the exponent. Note that 9 is a square of 3.

log9 = log3^2This means we can rewrite the logarithm as a product. log3^2= 2log3 Now we can substitute the given approximation for log3 and find log9.

2log3
2( 0.4771)
0.9542

Therefore, log9≈0.9542.

d

Finally, let's find the approximation of log50. To write it in terms of the given logarithms, we should first find factors of 50. Since 50 is even, we can divide it by 2.

log50=log( 2*25) By the Product Property, we can write the logarithm as a sum of logarithms. log(2*25)=log2+log25 Now, note that 25 is a square of 5. log2+log25=log2+log 5^2 According to the Power Property, we can rewrite the logarithm of a power as a product of the logarithm and the exponent. log2+log5^2=log2+ 2log5 Finally, we can substitute the given approximations.

log2+2log5
0.3010+2( 0.6990)
0.3010+1.398
1.6990

Therefore, log50≈1.6990.