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6 is the product of 2 and 3.
15 is the product of 3 and 5.
9 is the power of 3.
50 is divisible by 2 and 5.
log6≈0.7781
log15≈1.1761
log9≈0.9542
log50≈1.6990
We are given approximations of log2, log3, and log5. This allows us to approximate other logarithms. To do so, we will first recall three useful Properties of Logarithms.
| Properties of Logarithms | |||
|---|---|---|---|
| Name | Product Property | Quotient Property | Power Property |
| Condition | a>0, b>0, and x ≠1 | a>0, b>0, and x ≠1 | m>0, b>0, and b ≠1 |
| Property | log_x ab = log_x a + log_x b | log_x ab=log_x a - log_x b | log_b m^p = p log_b m |
To find the approximation of log6, we should write it in terms of the given logarithms. According to the Product Property, the logarithm of a product is the same as the sum of the logarithms of its factors. Note that
6 is a product of 2 and 3.
Therefore, log6≈0.7781.
Similarly as in Part A, we will use the Properties of Logarithms to write log15 in terms of the given logarithms. In this case, note that 15 is the product of 3 and 5.
log15 = log(3*5)
Therefore, log15≈ 1.1761.
Once again, to find the approximation of log9 we will use the Properties of Logarithms. According to the Power Property, the logarithm of a power is the product of the logarithm and the exponent. Note that 9 is a square of 3.
log9 = log3^2
Therefore, log9≈0.9542.
Finally, let's find the approximation of log50. To write it in terms of the given logarithms, we should first find factors of 50. Since 50 is even, we can divide it by 2.
log50=log( 2*25)
By the Product Property, we can write the logarithm as a sum of logarithms.
log2= 0.3010, log5= 0.6990
Multiply
Add terms
Therefore, log50≈1.6990.