Core Connections Algebra 2, 2013
CC
Core Connections Algebra 2, 2013 View details
1. Section 7.1
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Exercise 19 Page 321

Practice makes perfect
a

Let's first calculate the function's values for the given values of x.

x x^2+4x-5/x-1 f(x)
- 2 ( - 2)^2+4( - 2)-5/- 2-1 3
- 1 ( - 1)^2+4( - 1)-5/- 1-1 4
0 ( 0)^2+4( 0)-5/0-1 5
1 ( 1)^2+4( 1)-5/1-1 Undefined
2 ( 2)^2+4( 2)-5/2-1 7
3 ( 3)^2+4( 3)-5/3-1 8
Now we can complete the table. c|c|c|c|c|c|c x & - 2 & - 1 & 0 & 1 & 2 & 3 y & 3 & 4 & 5 & undefined & 7 & 8 Finally, we will graph the function. Notice that the function is not defined for x=1, which we can show as an open point.

b

From Part A, we see that the function is a straight line which means there is a linear relationship between x and y. Let's also calculate f(0.9) and f(1.1)

x x^2+4x-5/x-1 f(x)
0.9 ( 0.9)^2+4( 0.9)-5/0.9-1 5.9
1.1 ( 1.1)^2+4( 1.1)-5/1.1-1 6.1

Finally, we will add these points to the graph from Part A.

Notice that there is no asymptote at x=1. An asymptote is a straight line which a function approaches but never intersects. This is not the case with our function, as the function approaches a point and not a line.

c

To simplify the formula we have to rewrite the numerator by factoring the expression. If the expression can be factored, we should find two terms, a and b, whose sum equals the coefficient to x and whose product equals the constant.

cccll x^2 & + & 4x &+& -5 [0.3em] x^2 & + & (a+b)x & +& abLet's factor the product, - 5, in as many ways we can and add the factors. When the sum equals 4, we have identified the correct numbers a and b. c|c|c|cl product & a(b) & a+b & sum & [0.2em] [-1em] - 5 & - 5(1) & - 5+1& - 4 & * [0.1em] - 5& - 1(5) & - 1+5& 4 & ✓ By substituting a= - 1 and b= 5 into (x+a)(x+b), we will have factored the expression in the numerator. (x+( - 1))(x+ 5) ⇔ (x-1)(x+5) Now we can simplify the formula.

f(x)=x^2+4x-5/x-1
f(x)=(x-1)(x+5)/x-1
f(x)=x+5

The formula simplifies to f(x)=x+5. which means our conjecture in Part B was correct. There is in fact a linear relationship between x and y.