Core Connections Algebra 2, 2013
CC
Core Connections Algebra 2, 2013 View details
Chapter Closure

Exercise 148 Page 307

a

We want to mark the point (2,3,1) in a three-dimensional coordinate system. Let's begin by drawing three coordinate axes on isometric dot paper.

To find the point, we will go 2 steps in the x-axis positive direction, 3 steps in the y-axis positive direction, and 1 step in the z-axis positive direction.

b

Notice that the x-coordinate is negative. Let's extend all of the axes to include negative coordinates.

To find the point, we will go 2 steps in the negative direction of the x-axis and 3 steps in the positive direction of the y-axis.

c

To graph this equation, we need to determine where it intersects the x-, y-, and z-axes. We can do that by setting two of the variables equal to 0 and solving for the remaining variable.

|c|c|c| [-1em] Intercept & 2x+y-z=6 & (x,y,z) [0.2em] [-1em] x & 2x+0-9=6 & (3,0,0) [0.2em] [-1em] y & 2(0)+y-0=6 & (0,6,0) [0.2em] [-1em] z & 2(0)+0-z=6 & (0,0,-6) [0.2em] On isometric dot paper we will draw the x-, y-, and z-axis and then mark the coordinates of the intercepts. These points define a plane.