Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 4.2
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Exercise 97 Page 198

Practice makes perfect
a To graph y=x^2 we will first calculate some points in a value table.
|c|c|c| [-1em] x& x^2 & y [0.2em] [-1em] -4 & ( -4)^2 & 16 [0.2em] [-1em] -3 & ( -3)^2 & 9 [0.2em] [-1em] -2 & ( -2)^2 & 4 [0.2em] [-1em] -1 & ( -1)^2 & 1 [0.2em] [-1em] 0 & 0^2 & 0 [0.2em] [-1em] 1 & 1^2 & 1 [0.2em] [-1em] 2 & 2^2 & 4 [0.2em] [-1em] 3 & 3^2 & 9 [0.2em] [-1em] 4 & 4^2 & 16 [0.2em] Now we can graph the parabola. We will also draw a line through the points where the x-coordinate is -4 and 2.
To write the equation in slope-intercept form, we need to know the line's slope m and its y-intercept b. y=mx+b From the diagram, we can identify the y-intercept as b=8. To find the slope, we will substitute the two points into the Slope Formula and evaluate.
m = y_2 - y_1/x_2 - x_1
m = 16 - 4/- 4 - 2
Evaluate right-hand side
m = 12/- 6
m = - 12/6
m = - 2
By substituting b=8 and m=-2 we can write the line's equation. y=-2x+8
b Let's call the angle θ and mark it in the diagram.
To determine θ, we will add the following right triangle to the diagram.
Since we know the opposite and adjacent side to θ can can calculate the measure of θ by using the tangent ratio.
tan θ=Opposite/Adjacent
tanθ =4/2
Solve for θ
tan θ=2

tan^(-1)(LHS) = tan^(-1)(RHS)

θ=tan^(-1) 2
θ=63.43494...^(∘)
θ≈63.4^(∘)
Notice that we could also measure the obtuse angle that the line makes with the x-axis. Let's call this angle α.

Notice that ∠ θ and ∠ α make a Linear Pair which means they sum to 180^(∘). With this information, we can solve for ∠ α. 63.4^(∘)+ m ∠ α = 180^(∘) ⇕ m∠ α = 116.6^(∘)