Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 4.1
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Exercise 32 Page 177

Practice makes perfect
a To solve the given literal equation for y, we will use the Properties of Equality to apply inverse operations to the equation. Remember, only like terms can be combined.
5x-3y=12
5x=3y+12
5x-12=3y
5x-12/3=y
y=5x-12/3
b To solve the given literal equation for m_2, we will use the Properties of Equality to apply inverse operations to the equation. Remember, only like terms can be combined.
F=Gm_1m_2/r^2
Fr^2=Gm_1m_2
Fr^2/Gm_1=m_2
m_2=Fr^2/Gm_1
c To solve the given literal equation for m, we will use the Properties of Equality to apply inverse operations on the equation. Remember, only like terms can be combined.
E=1/2mv^2
E/v^2=1/2m
E/v^2=m/2
2*E/v^2=m
2E/v^2=m
m=2E/v^2
d To solve the given literal equation for y, we will use the Properties of Equality to apply inverse operations on the equation. Remember, only like terms can be combined.
(x-4)^2+(y-1)^2=10
(y-1)^2=10-(x-4)^2
sqrt((y-1)^2)=sqrt(10-(x-4)^2)
|y-1|=sqrt(10-(x-4)^2)
We have that the absolute value of y-1 is equal to sqrt(10-(x-4)^2). This means that we have two solutions, one positive and one negative. |y-1|=sqrt(10-(x-4)^2) ⇕ lc y-1 ≥ 0:y-1 = sqrt(10-(x-4)^2) & (I) y-1 < 0:y-1 = - (sqrt(10-(x-4)^2)) & (II) Now we can fully isolate y.
y-1=sqrt(10-(x-4)^2) y-1=-sqrt(10-(x-4)^2)
y=1+sqrt(10-(x-4)^2) y=1-sqrt(10-(x-4)^2)