Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 4.1
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Exercise 12 Page 172

Practice makes perfect
a To find the number of cubes when n=4, we must identify a pattern. Notice that the bigger cube's side equals the corresponding value of n. Therefore, n=4 correspond to a big cube with a side of 4 units.

However, notice that in each figure, there is always one cube missing from the top corner in the front. This should be the case for n=4 as well.

To obtain the number of small cubes when n=4, we must calculate the big cube's volume in terms of the smaller cubes and then subtract 1 to account for the smaller missing cube. Our formula becomes the following. n^3-1 Let's apply this formula when n=4.

n^3-1
4^3-1
â–¼
Evaluate right-hand side
64-1
63

The number of cubes is 63.

b From Part A, we established two things.
  • The big cube's side equals n.
  • The volume is 1 less than n^3.

Therefore, n= 1 must correspond to a big cube with a side of 1 unit. But since the volume of the figure is 1 less than this, we end up with no cube at all. 1^3-1=0

c From Part A, we found the general equation for the pattern. a_n=n^3-1 We also know that when n=1 there is no cube at all. Let's confirm this and also calculate the number of cubes when n=5.
|c|c|c| n & n^3-1 & = 1 & 1^3-1 & 0 5 & 5^3-1 & 124 There are 124 cubes in figure n=5.
d An arithmetic and geometric sequence differ in their progression.
Arithmetic: &Constant difference &between consecutive terms. &t(n)=d(x-1)+t(0) [0.7em] Geometric: &Constant factor &between consecutive terms. &t(n)=t(1)r^(n-1) Examining the equation from Part A, we notice that the sequence cannot be arithmetic as it contains a cubed variable. Also since the variable is in the base of a power, it cannot be geometric either. Therefore, its neither.